6k^2+0,36k=0

Solution for 6k^2+0,36k=0 equation:

6k^2+0.36k=0

a = 6; b = 0.36; c = 0;
Δ = b2-4ac
Δ = 0.362-4·6·0
Δ = 0.1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.36)-\sqrt{0.1296}}{2*6}=\frac{-0.36-\sqrt{0.1296}}{12}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.36)+\sqrt{0.1296}}{2*6}=\frac{-0.36+\sqrt{0.1296}}{12}
$